Adam has some green stickers and blue stickers.
If 62 green stickers are removed, 75% of the stickers will be blue stickers.
If 562 blue stickers are added, 30% of the stickers will be green stickers.
- How many green stickers are there?
- How many blue stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Blue |
Green |
Blue |
Before |
1 u + 62 |
3 u |
3 p |
7 p - 562 |
Change |
- 62 |
No change |
No change |
+ 562 |
After |
1 u |
3 u |
3 p |
7 p |
(a)
75% =
75100
=
34 30% =
30100 =
310 Scenario 1 Fraction of the stickers that are green in the end
= 1 -
34 =
14 Scenario 2
Fraction of the stickers that are green in the end
= 1 -
310 =
710 1 u + 62 = 3 p --- (1)
3 u = 7 p - 562 --- (2)
(1)
x 3 3 u + 186 = 3 p
3 u = 3 p - 186 --- (3)
(2) = (3)
7 p - 562 = 3 p - 186
7 p - 3 p = 562 - 186
4 p = 376
1 p = 376 ÷ 4 = 94
Number of green stickers
= 3 p
= 3 x 94
= 282
(b)
Number of blue stickers
= 7 p - 562
= 7 x 94 - 562
= 658 - 562
= 96
Answer(s): (a) 282; (b) 96