Adam has some red stickers and green stickers.
If 35 red stickers are removed, 75% of the stickers will be green stickers.
If 465 green stickers are added, 10% of the stickers will be red stickers.
- How many red stickers are there?
- How many green stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Red |
Green |
Red |
Green |
Before |
1 u + 35 |
3 u |
1 p |
9 p - 465 |
Change |
- 35 |
No change |
No change |
+ 465 |
After |
1 u |
3 u |
1 p |
9 p |
(a)
75% =
75100
=
34 10% =
10100 =
110 Scenario 1 Fraction of the stickers that are red in the end
= 1 -
34 =
14 Scenario 2
Fraction of the stickers that are red in the end
= 1 -
110 =
910 1 u + 35 = 1 p --- (1)
3 u = 9 p - 465 --- (2)
(1)
x 3 3 u + 105 = 3 p
3 u = 3 p - 105 --- (3)
(2) = (3)
9 p - 465 = 3 p - 105
9 p - 3 p = 465 - 105
6 p = 360
1 p = 360 ÷ 6 = 60
Number of red stickers
= 1 p
= 1 x 60
= 60
(b)
Number of green stickers
= 9 p - 465
= 9 x 60 - 465
= 540 - 465
= 75
Answer(s): (a) 60; (b) 75