Adam has some green stickers and blue stickers.
If 46 green stickers are removed, 75% of the stickers will be blue stickers.
If 420 blue stickers are added, 10% of the stickers will be green stickers.
- How many green stickers are there?
- How many blue stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Blue |
Green |
Blue |
Before |
1 u + 46 |
3 u |
1 p |
9 p - 420 |
Change |
- 46 |
No change |
No change |
+ 420 |
After |
1 u |
3 u |
1 p |
9 p |
(a)
75% =
75100
=
34 10% =
10100 =
110 Scenario 1 Fraction of the stickers that are green in the end
= 1 -
34 =
14 Scenario 2
Fraction of the stickers that are green in the end
= 1 -
110 =
910 1 u + 46 = 1 p --- (1)
3 u = 9 p - 420 --- (2)
(1)
x 3 3 u + 138 = 3 p
3 u = 3 p - 138 --- (3)
(2) = (3)
9 p - 420 = 3 p - 138
9 p - 3 p = 420 - 138
6 p = 282
1 p = 282 ÷ 6 = 47
Number of green stickers
= 1 p
= 1 x 47
= 47
(b)
Number of blue stickers
= 9 p - 420
= 9 x 47 - 420
= 423 - 420
= 3
Answer(s): (a) 47; (b) 3