Adam has some blue stickers and green stickers.
If 66 blue stickers are removed, 75% of the stickers will be green stickers.
If 498 green stickers are added, 30% of the stickers will be blue stickers.
- How many blue stickers are there?
- How many green stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Blue |
Green |
Blue |
Green |
Before |
1 u + 66 |
3 u |
3 p |
7 p - 498 |
Change |
- 66 |
No change |
No change |
+ 498 |
After |
1 u |
3 u |
3 p |
7 p |
(a)
75% =
75100
=
34 30% =
30100 =
310 Scenario 1 Fraction of the stickers that are blue in the end
= 1 -
34 =
14 Scenario 2
Fraction of the stickers that are blue in the end
= 1 -
310 =
710 1 u + 66 = 3 p --- (1)
3 u = 7 p - 498 --- (2)
(1)
x 3 3 u + 198 = 3 p
3 u = 3 p - 198 --- (3)
(2) = (3)
7 p - 498 = 3 p - 198
7 p - 3 p = 498 - 198
4 p = 300
1 p = 300 ÷ 4 = 75
Number of blue stickers
= 3 p
= 3 x 75
= 225
(b)
Number of green stickers
= 7 p - 498
= 7 x 75 - 498
= 525 - 498
= 27
Answer(s): (a) 225; (b) 27