Adam has some blue stickers and green stickers.
If 19 blue stickers are removed, 80% of the stickers will be green stickers.
If 535 green stickers are added, 30% of the stickers will be blue stickers.
- How many blue stickers are there?
- How many green stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Blue |
Green |
Blue |
Green |
Before |
1 u + 19 |
4 u |
3 p |
7 p - 535 |
Change |
- 19 |
No change |
No change |
+ 535 |
After |
1 u |
4 u |
3 p |
7 p |
(a)
80% =
80100
=
45 30% =
30100 =
310 Scenario 1 Fraction of the stickers that are blue in the end
= 1 -
45 =
15 Scenario 2
Fraction of the stickers that are blue in the end
= 1 -
310 =
710 1 u + 19 = 3 p --- (1)
4 u = 7 p - 535 --- (2)
(1)
x 4 4 u + 76 = 4 p
4 u = 4 p - 76 --- (3)
(2) = (3)
7 p - 535 = 4 p - 76
7 p - 4 p = 535 - 76
3 p = 459
1 p = 459 ÷ 3 = 153
Number of blue stickers
= 3 p
= 3 x 153
= 459
(b)
Number of green stickers
= 7 p - 535
= 7 x 153 - 535
= 1071 - 535
= 536
Answer(s): (a) 459; (b) 536