Adam has some blue stickers and green stickers.
If 31 blue stickers are removed, 80% of the stickers will be green stickers.
If 569 green stickers are added, 10% of the stickers will be blue stickers.
- How many blue stickers are there?
- How many green stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Blue |
Green |
Blue |
Green |
Before |
1 u + 31 |
4 u |
1 p |
9 p - 569 |
Change |
- 31 |
No change |
No change |
+ 569 |
After |
1 u |
4 u |
1 p |
9 p |
(a)
80% =
80100
=
45 10% =
10100 =
110 Scenario 1 Fraction of the stickers that are blue in the end
= 1 -
45 =
15 Scenario 2
Fraction of the stickers that are blue in the end
= 1 -
110 =
910 1 u + 31 = 1 p --- (1)
4 u = 9 p - 569 --- (2)
(1)
x 4 4 u + 124 = 4 p
4 u = 4 p - 124 --- (3)
(2) = (3)
9 p - 569 = 4 p - 124
9 p - 4 p = 569 - 124
5 p = 445
1 p = 445 ÷ 5 = 89
Number of blue stickers
= 1 p
= 1 x 89
= 89
(b)
Number of green stickers
= 9 p - 569
= 9 x 89 - 569
= 801 - 569
= 232
Answer(s): (a) 89; (b) 232