Adam has some blue stickers and green stickers.
If 24 blue stickers are removed, 80% of the stickers will be green stickers.
If 561 green stickers are added, 10% of the stickers will be blue stickers.
- How many blue stickers are there?
- How many green stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Blue |
Green |
Blue |
Green |
Before |
1 u + 24 |
4 u |
1 p |
9 p - 561 |
Change |
- 24 |
No change |
No change |
+ 561 |
After |
1 u |
4 u |
1 p |
9 p |
(a)
80% =
80100
=
45 10% =
10100 =
110 Scenario 1 Fraction of the stickers that are blue in the end
= 1 -
45 =
15 Scenario 2
Fraction of the stickers that are blue in the end
= 1 -
110 =
910 1 u + 24 = 1 p --- (1)
4 u = 9 p - 561 --- (2)
(1)
x 4 4 u + 96 = 4 p
4 u = 4 p - 96 --- (3)
(2) = (3)
9 p - 561 = 4 p - 96
9 p - 4 p = 561 - 96
5 p = 465
1 p = 465 ÷ 5 = 93
Number of blue stickers
= 1 p
= 1 x 93
= 93
(b)
Number of green stickers
= 9 p - 561
= 9 x 93 - 561
= 837 - 561
= 276
Answer(s): (a) 93; (b) 276