Adam has some green stickers and blue stickers.
If 15 green stickers are removed, 80% of the stickers will be blue stickers.
If 525 blue stickers are added, 10% of the stickers will be green stickers.
- How many green stickers are there?
- How many blue stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Blue |
Green |
Blue |
Before |
1 u + 15 |
4 u |
1 p |
9 p - 525 |
Change |
- 15 |
No change |
No change |
+ 525 |
After |
1 u |
4 u |
1 p |
9 p |
(a)
80% =
80100
=
45 10% =
10100 =
110 Scenario 1 Fraction of the stickers that are green in the end
= 1 -
45 =
15 Scenario 2
Fraction of the stickers that are green in the end
= 1 -
110 =
910 1 u + 15 = 1 p --- (1)
4 u = 9 p - 525 --- (2)
(1)
x 4 4 u + 60 = 4 p
4 u = 4 p - 60 --- (3)
(2) = (3)
9 p - 525 = 4 p - 60
9 p - 4 p = 525 - 60
5 p = 465
1 p = 465 ÷ 5 = 93
Number of green stickers
= 1 p
= 1 x 93
= 93
(b)
Number of blue stickers
= 9 p - 525
= 9 x 93 - 525
= 837 - 525
= 312
Answer(s): (a) 93; (b) 312