Adam has some blue stickers and red stickers.
If 51 blue stickers are removed, 80% of the stickers will be red stickers.
If 529 red stickers are added, 10% of the stickers will be blue stickers.
- How many blue stickers are there?
- How many red stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Blue |
Red |
Blue |
Red |
Before |
1 u + 51 |
4 u |
1 p |
9 p - 529 |
Change |
- 51 |
No change |
No change |
+ 529 |
After |
1 u |
4 u |
1 p |
9 p |
(a)
80% =
80100
=
45 10% =
10100 =
110 Scenario 1 Fraction of the stickers that are blue in the end
= 1 -
45 =
15 Scenario 2
Fraction of the stickers that are blue in the end
= 1 -
110 =
910 1 u + 51 = 1 p --- (1)
4 u = 9 p - 529 --- (2)
(1)
x 4 4 u + 204 = 4 p
4 u = 4 p - 204 --- (3)
(2) = (3)
9 p - 529 = 4 p - 204
9 p - 4 p = 529 - 204
5 p = 325
1 p = 325 ÷ 5 = 65
Number of blue stickers
= 1 p
= 1 x 65
= 65
(b)
Number of red stickers
= 9 p - 529
= 9 x 65 - 529
= 585 - 529
= 56
Answer(s): (a) 65; (b) 56