Adam has some green stickers and blue stickers.
If 10 green stickers are removed, 80% of the stickers will be blue stickers.
If 555 blue stickers are added, 10% of the stickers will be green stickers.
- How many green stickers are there?
- How many blue stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Blue |
Green |
Blue |
Before |
1 u + 10 |
4 u |
1 p |
9 p - 555 |
Change |
- 10 |
No change |
No change |
+ 555 |
After |
1 u |
4 u |
1 p |
9 p |
(a)
80% =
80100
=
45 10% =
10100 =
110 Scenario 1 Fraction of the stickers that are green in the end
= 1 -
45 =
15 Scenario 2
Fraction of the stickers that are green in the end
= 1 -
110 =
910 1 u + 10 = 1 p --- (1)
4 u = 9 p - 555 --- (2)
(1)
x 4 4 u + 40 = 4 p
4 u = 4 p - 40 --- (3)
(2) = (3)
9 p - 555 = 4 p - 40
9 p - 4 p = 555 - 40
5 p = 515
1 p = 515 ÷ 5 = 103
Number of green stickers
= 1 p
= 1 x 103
= 103
(b)
Number of blue stickers
= 9 p - 555
= 9 x 103 - 555
= 927 - 555
= 372
Answer(s): (a) 103; (b) 372