Adam has some red stickers and blue stickers.
If 26 red stickers are removed, 80% of the stickers will be blue stickers.
If 544 blue stickers are added, 10% of the stickers will be red stickers.
- How many red stickers are there?
- How many blue stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Red |
Blue |
Red |
Blue |
Before |
1 u + 26 |
4 u |
1 p |
9 p - 544 |
Change |
- 26 |
No change |
No change |
+ 544 |
After |
1 u |
4 u |
1 p |
9 p |
(a)
80% =
80100
=
45 10% =
10100 =
110 Scenario 1 Fraction of the stickers that are red in the end
= 1 -
45 =
15 Scenario 2
Fraction of the stickers that are red in the end
= 1 -
110 =
910 1 u + 26 = 1 p --- (1)
4 u = 9 p - 544 --- (2)
(1)
x 4 4 u + 104 = 4 p
4 u = 4 p - 104 --- (3)
(2) = (3)
9 p - 544 = 4 p - 104
9 p - 4 p = 544 - 104
5 p = 440
1 p = 440 ÷ 5 = 88
Number of red stickers
= 1 p
= 1 x 88
= 88
(b)
Number of blue stickers
= 9 p - 544
= 9 x 88 - 544
= 792 - 544
= 248
Answer(s): (a) 88; (b) 248