Adam has some red stickers and green stickers.
If 34 red stickers are removed, 80% of the stickers will be green stickers.
If 416 green stickers are added, 10% of the stickers will be red stickers.
- How many red stickers are there?
- How many green stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Red |
Green |
Red |
Green |
Before |
1 u + 34 |
4 u |
1 p |
9 p - 416 |
Change |
- 34 |
No change |
No change |
+ 416 |
After |
1 u |
4 u |
1 p |
9 p |
(a)
80% =
80100
=
45 10% =
10100 =
110 Scenario 1 Fraction of the stickers that are red in the end
= 1 -
45 =
15 Scenario 2
Fraction of the stickers that are red in the end
= 1 -
110 =
910 1 u + 34 = 1 p --- (1)
4 u = 9 p - 416 --- (2)
(1)
x 4 4 u + 136 = 4 p
4 u = 4 p - 136 --- (3)
(2) = (3)
9 p - 416 = 4 p - 136
9 p - 4 p = 416 - 136
5 p = 280
1 p = 280 ÷ 5 = 56
Number of red stickers
= 1 p
= 1 x 56
= 56
(b)
Number of green stickers
= 9 p - 416
= 9 x 56 - 416
= 504 - 416
= 88
Answer(s): (a) 56; (b) 88