Adam has some blue stickers and green stickers.
If 77 blue stickers are removed, 80% of the stickers will be green stickers.
If 587 green stickers are added, 30% of the stickers will be blue stickers.
- How many blue stickers are there?
- How many green stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Blue |
Green |
Blue |
Green |
Before |
1 u + 77 |
4 u |
3 p |
7 p - 587 |
Change |
- 77 |
No change |
No change |
+ 587 |
After |
1 u |
4 u |
3 p |
7 p |
(a)
80% =
80100
=
45 30% =
30100 =
310 Scenario 1 Fraction of the stickers that are blue in the end
= 1 -
45 =
15 Scenario 2
Fraction of the stickers that are blue in the end
= 1 -
310 =
710 1 u + 77 = 3 p --- (1)
4 u = 7 p - 587 --- (2)
(1)
x 4 4 u + 308 = 4 p
4 u = 4 p - 308 --- (3)
(2) = (3)
7 p - 587 = 4 p - 308
7 p - 4 p = 587 - 308
3 p = 279
1 p = 279 ÷ 3 = 93
Number of blue stickers
= 3 p
= 3 x 93
= 279
(b)
Number of green stickers
= 7 p - 587
= 7 x 93 - 587
= 651 - 587
= 64
Answer(s): (a) 279; (b) 64