Adam has some green stickers and blue stickers.
If 41 green stickers are removed, 75% of the stickers will be blue stickers.
If 471 blue stickers are added, 10% of the stickers will be green stickers.
- How many green stickers are there?
- How many blue stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Green |
Blue |
Green |
Blue |
Before |
1 u + 41 |
3 u |
1 p |
9 p - 471 |
Change |
- 41 |
No change |
No change |
+ 471 |
After |
1 u |
3 u |
1 p |
9 p |
(a)
75% =
75100
=
34 10% =
10100 =
110 Scenario 1 Fraction of the stickers that are green in the end
= 1 -
34 =
14 Scenario 2
Fraction of the stickers that are green in the end
= 1 -
110 =
910 1 u + 41 = 1 p --- (1)
3 u = 9 p - 471 --- (2)
(1)
x 3 3 u + 123 = 3 p
3 u = 3 p - 123 --- (3)
(2) = (3)
9 p - 471 = 3 p - 123
9 p - 3 p = 471 - 123
6 p = 348
1 p = 348 ÷ 6 = 58
Number of green stickers
= 1 p
= 1 x 58
= 58
(b)
Number of blue stickers
= 9 p - 471
= 9 x 58 - 471
= 522 - 471
= 51
Answer(s): (a) 58; (b) 51