Adam has some blue stickers and red stickers.
If 53 blue stickers are removed, 75% of the stickers will be red stickers.
If 597 red stickers are added, 10% of the stickers will be blue stickers.
- How many blue stickers are there?
- How many red stickers are there?
|
Scenario 1 |
Scenario 2 |
|
Blue |
Red |
Blue |
Red |
Before |
1 u + 53 |
3 u |
1 p |
9 p - 597 |
Change |
- 53 |
No change |
No change |
+ 597 |
After |
1 u |
3 u |
1 p |
9 p |
(a)
75% =
75100
=
34 10% =
10100 =
110 Scenario 1 Fraction of the stickers that are blue in the end
= 1 -
34 =
14 Scenario 2
Fraction of the stickers that are blue in the end
= 1 -
110 =
910 1 u + 53 = 1 p --- (1)
3 u = 9 p - 597 --- (2)
(1)
x 3 3 u + 159 = 3 p
3 u = 3 p - 159 --- (3)
(2) = (3)
9 p - 597 = 3 p - 159
9 p - 3 p = 597 - 159
6 p = 438
1 p = 438 ÷ 6 = 73
Number of blue stickers
= 1 p
= 1 x 73
= 73
(b)
Number of red stickers
= 9 p - 597
= 9 x 73 - 597
= 657 - 597
= 60
Answer(s): (a) 73; (b) 60