Adam has some green stickers and blue stickers.
If 33 green stickers are removed, 80% of the stickers will be blue stickers.
If 582 blue stickers are added, 30% of the stickers will be green stickers.

1. How many green stickers are there?
2. How many blue stickers are there?

	Scenario 1		Scenario 2
	Green	Blue	Green	Blue
Before	1 u + 33	4 u	3 p	7 p - 582
Change	- 33	No change	No change	+ 582
After	1 u	4 u	3 p	7 p

(a)
80% = ⁸⁰₁₀₀
= ⁴₅
30% = ³⁰₁₀₀ = ³₁₀

Scenario 1 
Fraction of the stickers that are green in the end
= 1 - ⁴₅
= ¹₅ 

Scenario 2
Fraction of the stickers that are green in the end
= 1 - ³₁₀
= ⁷₁₀ 

1 u + 33 = 3 p --- (1)
4 u = 7 p - 582 --- (2)

(1) _{x 4}
4 u + 132 = 4 p
4 u = 4 p - 132 --- (3)

(2) = (3)
7 p - 582 = 4 p - 132
7 p - 4 p = 582 - 132
3 p = 450

1 p = 450 ÷ 3 = 150

Number of green stickers
= 3 p
= 3 x 150
= 450

(b)
Number of blue stickers
= 7 p - 582
= 7 x 150 - 582
= 1050 - 582
= 468

Answer(s): (a) 450; (b) 468