The average cost of some books is $42.
If 3 of the books are now each $10 more,
the average cost of the books becomes $44.
How many books are there altogether?
|
Case 1 |
Case 2 |
Number |
1 u |
1 u |
Value |
42 |
44 |
Total value |
42 u |
44 u |
Number of books at first = 1 u
Number of books in the end = 1 u
Total cost of the books at first
= 42 x 1 u
= 42 u
Total cost of books in the end
= 44 x 1 u
= 44 u
Increase in the cost when 3 books are now each $10 more
= 3 x 10
= $30
Total cost of books after 3 books are now each $10 more
= 42 u + 30
44 u = 42 u + 30
44 u - 42 u = 30
2 u = 30
1 u = 30 ÷ 2 = 15
Number of books in the end
= 1 u
= 15
Answer(s): 15