The average cost of some books is $60.
If 7 of the books are now each $8 more and
4 of the books are now each $5 less,
the average cost of the books becomes $62.
How many books are there altogether?
|
Case 1 |
Case 2 |
Number |
1 u |
1 u |
Value |
60 |
62 |
Total value |
60 u |
62 u |
Number of books at first = 1 u
Number of books in the end = 1 u
Total cost of the books at first
= 60 x 1 u
= 60 u
Increase in the cost after 7 books are now each $8 more and 4 books are now each $5 less
= 7 x 8 - 4 x 5
= 56 - 20
= $36
Total cost of books after 7 books are now each $8 more and 4 books are now each $5 less
= 60 u + 36
Total cost of books in the end
= 62 x 1 u
= 62 u
62 u = 60 u + 36
62 u - 60 u = 36
2 u = 36
1 u = 36 ÷ 2 = 18
Number of books in the end
= 1 u
= 18
Answer(s): 18