The average cost of some books is $40.
If 9 of the books are now each $12 more and
4 of the books are now each $6 less,
the average cost of the books becomes $43.
How many books are there altogether?
|
Case 1 |
Case 2 |
Number |
1 u |
1 u |
Value |
40 |
43 |
Total value |
40 u |
43 u |
Number of books at first = 1 u
Number of books in the end = 1 u
Total cost of the books at first
= 40 x 1 u
= 40 u
Increase in the cost after 9 books are now each $12 more and 4 books are now each $6 less
= 9 x 12 - 4 x 6
= 108 - 24
= $84
Total cost of books after 9 books are now each $12 more and 4 books are now each $6 less
= 40 u + 84
Total cost of books in the end
= 43 x 1 u
= 43 u
43 u = 40 u + 84
43 u - 40 u = 84
3 u = 84
1 u = 84 ÷ 3 = 28
Number of books in the end
= 1 u
= 28
Answer(s): 28