The average cost of some books is $25.
If 9 of the books are now each $8 more and
4 of the books are now each $7 less,
the average cost of the books becomes $27.
How many books are there altogether?
|
Case 1 |
Case 2 |
Number |
1 u |
1 u |
Value |
25 |
27 |
Total value |
25 u |
27 u |
Number of books at first = 1 u
Number of books in the end = 1 u
Total cost of the books at first
= 25 x 1 u
= 25 u
Increase in the cost after 9 books are now each $8 more and 4 books are now each $7 less
= 9 x 8 - 4 x 7
= 72 - 28
= $44
Total cost of books after 9 books are now each $8 more and 4 books are now each $7 less
= 25 u + 44
Total cost of books in the end
= 27 x 1 u
= 27 u
27 u = 25 u + 44
27 u - 25 u = 44
2 u = 44
1 u = 44 ÷ 2 = 22
Number of books in the end
= 1 u
= 22
Answer(s): 22