The average cost of some books is $50.
If 9 of the books are now each $9 more and
7 of the books are now each $5 less,
the average cost of the books becomes $52.
How many books are there altogether?
|
Case 1 |
Case 2 |
Number |
1 u |
1 u |
Value |
50 |
52 |
Total value |
50 u |
52 u |
Number of books at first = 1 u
Number of books in the end = 1 u
Total cost of the books at first
= 50 x 1 u
= 50 u
Increase in the cost after 9 books are now each $9 more and 7 books are now each $5 less
= 9 x 9 - 7 x 5
= 81 - 35
= $46
Total cost of books after 9 books are now each $9 more and 7 books are now each $5 less
= 50 u + 46
Total cost of books in the end
= 52 x 1 u
= 52 u
52 u = 50 u + 46
52 u - 50 u = 46
2 u = 46
1 u = 46 ÷ 2 = 23
Number of books in the end
= 1 u
= 23
Answer(s): 23