The average cost of some books is $50.
If 6 of the books are now each $13 more and
4 of the books are now each $6 less,
the average cost of the books becomes $52.
How many books are there altogether?
|
Case 1 |
Case 2 |
Number |
1 u |
1 u |
Value |
50 |
52 |
Total value |
50 u |
52 u |
Number of books at first = 1 u
Number of books in the end = 1 u
Total cost of the books at first
= 50 x 1 u
= 50 u
Increase in the cost after 6 books are now each $13 more and 4 books are now each $6 less
= 6 x 13 - 4 x 6
= 78 - 24
= $54
Total cost of books after 6 books are now each $13 more and 4 books are now each $6 less
= 50 u + 54
Total cost of books in the end
= 52 x 1 u
= 52 u
52 u = 50 u + 54
52 u - 50 u = 54
2 u = 54
1 u = 54 ÷ 2 = 27
Number of books in the end
= 1 u
= 27
Answer(s): 27