The average cost of some books is $55.
If 7 of the books are now each $14 more and
2 of the books are now each $7 less,
the average cost of the books becomes $57.
How many books are there altogether?
|
Case 1 |
Case 2 |
Number |
1 u |
1 u |
Value |
55 |
57 |
Total value |
55 u |
57 u |
Number of books at first = 1 u
Number of books in the end = 1 u
Total cost of the books at first
= 55 x 1 u
= 55 u
Increase in the cost after 7 books are now each $14 more and 2 books are now each $7 less
= 7 x 14 - 2 x 7
= 98 - 14
= $84
Total cost of books after 7 books are now each $14 more and 2 books are now each $7 less
= 55 u + 84
Total cost of books in the end
= 57 x 1 u
= 57 u
57 u = 55 u + 84
57 u - 55 u = 84
2 u = 84
1 u = 84 ÷ 2 = 42
Number of books in the end
= 1 u
= 42
Answer(s): 42