Adam has a total of 12 chickens and buffaloes.
The difference in their number of legs is 12.
How many (a) buffaloes and (b) chickens does Adam have?
Number of
chickens |
Number of
chickens' legs |
Number of
buffaloes |
Number of
buffaloes' legs |
Difference in the
number of legs |
| 12 |
12 x 2 =
24 |
0 |
0 x 4 =
4 |
24 - 0 =
24 |
| 11 |
11 x 2 =
22 |
1 |
1 x 4 =
4 |
22 - 4 =
18 |
| 10 |
10 x 2 =
20 |
2 |
10 x 4 =
8 |
20 - 8 =
12 |
If all of the animals are chickens,
the number of legs needed
= 12 x 2
= 24
Total difference in the number of legs
= 24 - 12
= 12
Difference in the number of legs when 1 chicken is replaced by 1 buffalo
= 24 - 18
= 6
Number of buffaloes
= 12 ÷ 6
= 2 (a)
Number of chickens
= 12 - 2
= 10 (b)
Answer(s): (a) 2; (b) 10
