Adam has a total of 14 hens and buffaloes.
The number of buffaloes' legs is 20 more than the hens' legs.
How many (a) hens and (b) buffaloes does Adam have?
| Number of buffaloes |
Number of buffaloes' legs |
Number of hens |
Number of hens' legs |
Number of more
buffaloes' legs than hens' legs |
14
|
14 x 4 =
56 |
0 |
0 x 2 =
0 |
56 - 0 =
56 |
| 13 |
13 x 4 =
52 |
1 |
1 x 2 =
2 |
52 - 2 =
50 |
| 8 |
8 x 4 =
32 |
6 |
6 x 2 =
12 |
32 - 12 =
20 |
(a)
If Adam has 14 buffaloes,
the number of legs
= 14 x 4
= 56
If Adam has 13 buffaloes and 1 hen,
number of more buffaloes' legs than hens' legs
= 13 x 4 - 1 x 2
= 52 - 2
= 50
Decrease in the number of legs when 1 buffalo is replaced by 1 hen
= 56 - 50
= 6
Total decrease in the number of legs
= 56 - 20
= 36
Number of hens
= 36 ÷ 6
= 6
(b)
Number of buffaloes
= 14 - 6
= 8
Answer(s): (a) 6; (b) 8
