Adam has a total of 14 chicken and donkeys.
The number of donkeys' legs is 32 more than the chicken' legs.
How many (a) chicken and (b) donkeys does Adam have?
| Number of donkeys |
Number of donkeys' legs |
Number of chicken |
Number of chicken' legs |
Number of more
donkeys' legs than chicken' legs |
14
|
14 x 4 =
56 |
0 |
0 x 2 =
0 |
56 - 0 =
56 |
| 13 |
13 x 4 =
52 |
1 |
1 x 2 =
2 |
52 - 2 =
50 |
| 10 |
10 x 4 =
40 |
4 |
4 x 2 =
8 |
40 - 8 =
32 |
(a)
If Adam has 14 donkeys,
the number of legs
= 14 x 4
= 56
If Adam has 13 donkeys and 1 chicken,
number of more donkeys' legs than chicken' legs
= 13 x 4 - 1 x 2
= 52 - 2
= 50
Decrease in the number of legs when 1 donkey is replaced by 1 chicken
= 56 - 50
= 6
Total decrease in the number of legs
= 56 - 32
= 24
Number of chicken
= 24 ÷ 6
= 4
(b)
Number of donkeys
= 14 - 4
= 10
Answer(s): (a) 4; (b) 10
