Adam has a total of 10 geese and cows.
The number of cows' legs is 16 more than the geese' legs.
How many (a) geese and (b) cows does Adam have?
| Number of cows |
Number of cows' legs |
Number of geese |
Number of geese' legs |
Number of more
cows' legs than geese' legs |
10
|
10 x 4 =
40 |
0 |
0 x 2 =
0 |
40 - 0 =
40 |
| 9 |
9 x 4 =
36 |
1 |
1 x 2 =
2 |
36 - 2 =
34 |
| 6 |
6 x 4 =
24 |
4 |
4 x 2 =
8 |
24 - 8 =
16 |
(a)
If Adam has 10 cows,
the number of legs
= 10 x 4
= 40
If Adam has 9 cows and 1 goose,
number of more cows' legs than geese' legs
= 9 x 4 - 1 x 2
= 36 - 2
= 34
Decrease in the number of legs when 1 cow is replaced by 1 goose
= 40 - 34
= 6
Total decrease in the number of legs
= 40 - 16
= 24
Number of geese
= 24 ÷ 6
= 4
(b)
Number of cows
= 10 - 4
= 6
Answer(s): (a) 4; (b) 6
