Adam has a total of 10 chicken and pigs.
The number of pigs' legs is 16 more than the chicken' legs.
How many (a) chicken and (b) pigs does Adam have?
| Number of pigs |
Number of pigs' legs |
Number of chicken |
Number of chicken' legs |
Number of more
pigs' legs than chicken' legs |
10
|
10 x 4 =
40 |
0 |
0 x 2 =
0 |
40 - 0 =
40 |
| 9 |
9 x 4 =
36 |
1 |
1 x 2 =
2 |
36 - 2 =
34 |
| 6 |
6 x 4 =
24 |
4 |
4 x 2 =
8 |
24 - 8 =
16 |
(a)
If Adam has 10 pigs,
the number of legs
= 10 x 4
= 40
If Adam has 9 pigs and 1 chicken,
number of more pigs' legs than chicken' legs
= 9 x 4 - 1 x 2
= 36 - 2
= 34
Decrease in the number of legs when 1 pig is replaced by 1 chicken
= 40 - 34
= 6
Total decrease in the number of legs
= 40 - 16
= 24
Number of chicken
= 24 ÷ 6
= 4
(b)
Number of pigs
= 10 - 4
= 6
Answer(s): (a) 4; (b) 6
