Adam has a total of 15 geese and buffaloes.
The number of geese' legs is 24 less than the buffaloes' legs.
How many (a) geese and (b) buffaloes does Adam have?
| Number of buffaloes |
Number of buffaloes' legs |
Number of geese |
Number of geese' legs |
Number of less
geese' legs than buffaloes' legs |
15
|
15 x 4 =
60 |
0 |
0 x 2 =
0 |
60 - 0 =
60 |
| 14 |
14 x 4 =
56 |
1 |
1 x 2 =
2 |
56 - 2 =
54 |
| 9 |
9 x 4 =
36 |
6 |
6 x 2 =
12 |
36 - 12 =
24 |
(a)
If Adam has 15 buffaloes,
the number of legs
= 15 x 4
= 60
If Adam has 14 buffaloes and 1 goose,
number of less geese' legs than buffaloes' legs
= 14 x 4 - 1 x 2
= 56 - 2
= 54
Decrease in the number of legs when 1 buffalo is replaced by a 1 goose
= 60 - 54
= 6
Total decrease in the number of legs
= 60 - 24
= 36
Number of geese
= 36 ÷ 6
= 6
(b)
Number of buffaloes
= 15 - 6
= 9
Answer(s): (a) 6; (b) 9
