Adam has a total of 20 hens and donkeys.
The number of hens' legs is 14 less than the donkeys' legs.
How many (a) hens and (b) donkeys does Adam have?
Number of donkeys |
Number of donkeys' legs |
Number of hens |
Number of hens' legs |
Number of less hens' legs than donkeys' legs |
20
|
20 x 4 = 80 |
0 |
0 x 2 = 0 |
80 - 0 = 80 |
19 |
19 x 4 = 76 |
1 |
1 x 2 = 2 |
76 - 2 = 74 |
9 |
9 x 4 = 36 |
11 |
11 x 2 = 22 |
36 - 22 = 14 |
(a)
If Adam has 20 donkeys,
the number of legs
= 20 x 4
= 80
If Adam has 19 donkeys and 1 hen,
number of less hens' legs than donkeys' legs
= 19 x 4 - 1 x 2
= 76 - 2
= 74
Decrease in the number of legs when 1 donkey is replaced by a 1 hen
= 80 - 74
= 6
Total decrease in the number of legs
= 80 - 14
= 66
Number of hens
= 66 ÷ 6
= 11
(b)
Number of donkeys
= 20 - 11
= 9
Answer(s): (a) 11; (b) 9