Fill in the blanks.
Adam has seven times as many stickers as Charlie.
Adam gives 60 to Bryan.
Charlie receives 60 from Bryan.
In the end, Adam has four times as many stickers as Charlie.
- Change in the number of stickers Charlie has = _____ u
- Difference in the number of stickers Adam and Charlie have in the end = _____ u
- _____ u = 60
- 1 u = _____
|
Adam |
Bryan |
Charlie |
Total of Adam and Charlie |
Before |
7x5 |
not given |
1x5 |
8x5 |
Change 1 |
- 60 |
+ 60 |
|
|
Change 2 |
|
- 60 |
+ 60 |
|
After |
4x8 |
not given |
1x8 |
5x8 |
|
Adam |
Bryan |
Charlie |
Total of Adam and Charlie |
Before |
35 u |
not given |
5 u |
40 u |
Change 1 |
- 60 |
+ 60 |
|
|
Change 2 |
|
- 60 |
+ 60 |
|
After |
32 u |
not given |
8 u |
40 u |
(a)
Change X times into units.
The total number of stickers of Adam and Charlie remains unchanged.
LCM of 8 and 5 is 40.
Change in the number of stickers that Charlie has
= 8 u - 5 u
= 3 u
(b)
Difference in the number that Adam and Charlie has in the end
= 32 u - 8 u
= 24 u
(c)
3 u = 60
(d)
1 u = 60 ÷ 3 = 20
Answer(s): (a) 3; (b) 24; (c) 3; (d) 20