Fill in the blanks.
Charlie has six times as many stickers as Adam.
Charlie gives 100 to Bryan.
Adam receives 100 from Bryan.
In the end, Charlie has twice as many stickers as Adam.
- Change in the number of stickers Adam has = _____ u
- Difference in the number of stickers Charlie and Adam have in the end = _____ u
- _____ u = 100
- 1 u = _____
|
Charlie |
Bryan |
Adam |
Total of Charlie and Adam |
Before |
6x3 |
not given |
1x3 |
7x3 |
Change 1 |
- 100 |
+ 100 |
|
|
Change 2 |
|
- 100 |
+ 100 |
|
After |
2x7 |
not given |
1x7 |
3x7 |
|
Charlie |
Bryan |
Adam |
Total of Charlie and Adam |
Before |
18 u |
not given |
3 u |
21 u |
Change 1 |
- 100 |
+ 100 |
|
|
Change 2 |
|
- 100 |
+ 100 |
|
After |
14 u |
not given |
7 u |
21 u |
(a)
Change X times into units.
The total number of stickers of Charlie and Adam remains unchanged.
LCM of 7 and 3 is 21.
Change in the number of stickers that Adam has
= 7 u - 3 u
= 4 u
(b)
Difference in the number that Charlie and Adam has in the end
= 14 u - 7 u
= 7 u
(c)
4 u = 100
(d)
1 u = 100 ÷ 4 = 25
Answer(s): (a) 4; (b) 7; (c) 4; (d) 25