Fill in the blanks.
Adam has four times as many stickers as Bryan.
Adam gives 20 to Charlie.
Bryan receives 20 from Charlie.
In the end, Adam has twice as many stickers as Bryan.
- Change in the number of stickers Bryan has = _____ u
- Difference in the number of stickers Adam and Bryan have in the end = _____ u
- _____ u = 20
- 1 u = _____
|
Adam |
Charlie |
Bryan |
Total of Adam and Bryan |
Before |
4x3 |
not given |
1x3 |
5x3 |
Change 1 |
- 20 |
+ 20 |
|
|
Change 2 |
|
- 20 |
+ 20 |
|
After |
2x5 |
not given |
1x5 |
3x5 |
|
Adam |
Charlie |
Bryan |
Total of Adam and Bryan |
Before |
12 u |
not given |
3 u |
15 u |
Change 1 |
- 20 |
+ 20 |
|
|
Change 2 |
|
- 20 |
+ 20 |
|
After |
10 u |
not given |
5 u |
15 u |
(a)
Change X times into units.
The total number of stickers of Adam and Bryan remains unchanged.
LCM of 5 and 3 is 15.
Change in the number of stickers that Bryan has
= 5 u - 3 u
= 2 u
(b)
Difference in the number that Adam and Bryan has in the end
= 10 u - 5 u
= 5 u
(c)
2 u = 20
(d)
1 u = 20 ÷ 2 = 10
Answer(s): (a) 2; (b) 5; (c) 2; (d) 10