Fill in the blanks.
Bryan has six times as many stickers as Adam.
Bryan gives 90 to Charlie.
Adam receives 90 from Charlie.
In the end, Bryan has four times as many stickers as Adam.
- Change in the number of stickers Adam has = _____ u
- Difference in the number of stickers Bryan and Adam have in the end = _____ u
- _____ u = 90
- 1 u = _____
|
Bryan |
Charlie |
Adam |
Total of Bryan and Adam |
Before |
6x5 |
not given |
1x5 |
7x5 |
Change 1 |
- 90 |
+ 90 |
|
|
Change 2 |
|
- 90 |
+ 90 |
|
After |
4x7 |
not given |
1x7 |
5x7 |
|
Bryan |
Charlie |
Adam |
Total of Bryan and Adam |
Before |
30 u |
not given |
5 u |
35 u |
Change 1 |
- 90 |
+ 90 |
|
|
Change 2 |
|
- 90 |
+ 90 |
|
After |
28 u |
not given |
7 u |
35 u |
(a)
Change X times into units.
The total number of stickers of Bryan and Adam remains unchanged.
LCM of 7 and 5 is 35.
Change in the number of stickers that Adam has
= 7 u - 5 u
= 2 u
(b)
Difference in the number that Bryan and Adam has in the end
= 28 u - 7 u
= 21 u
(c)
2 u = 90
(d)
1 u = 90 ÷ 2 = 45
Answer(s): (a) 2; (b) 21; (c) 2; (d) 45