Fill in the blanks.
Bryan has four times as many stickers as Charlie.
Bryan gives 80 to Adam.
Charlie receives 80 from Adam.
In the end, Bryan has twice as many stickers as Charlie.
- Change in the number of stickers Charlie has = _____ u
- Difference in the number of stickers Bryan and Charlie have in the end = _____ u
- _____ u = 80
- 1 u = _____
|
Bryan |
Adam |
Charlie |
Total of Bryan and Charlie |
Before |
4x3 |
not given |
1x3 |
5x3 |
Change 1 |
- 80 |
+ 80 |
|
|
Change 2 |
|
- 80 |
+ 80 |
|
After |
2x5 |
not given |
1x5 |
3x5 |
|
Bryan |
Adam |
Charlie |
Total of Bryan and Charlie |
Before |
12 u |
not given |
3 u |
15 u |
Change 1 |
- 80 |
+ 80 |
|
|
Change 2 |
|
- 80 |
+ 80 |
|
After |
10 u |
not given |
5 u |
15 u |
(a)
Change X times into units.
The total number of stickers of Bryan and Charlie remains unchanged.
LCM of 5 and 3 is 15.
Change in the number of stickers that Charlie has
= 5 u - 3 u
= 2 u
(b)
Difference in the number that Bryan and Charlie has in the end
= 10 u - 5 u
= 5 u
(c)
2 u = 80
(d)
1 u = 80 ÷ 2 = 40
Answer(s): (a) 2; (b) 5; (c) 2; (d) 40