Fill in the blanks.
Charlie has six times as many stickers as Bryan.
Charlie gives 20 to Adam.
Bryan receives 20 from Adam.
In the end, Charlie has twice as many stickers as Bryan.
- Change in the number of stickers Bryan has = _____ u
- Difference in the number of stickers Charlie and Bryan have in the end = _____ u
- _____ u = 20
- 1 u = _____
|
Charlie |
Adam |
Bryan |
Total of Charlie and Bryan |
Before |
6x3 |
not given |
1x3 |
7x3 |
Change 1 |
- 20 |
+ 20 |
|
|
Change 2 |
|
- 20 |
+ 20 |
|
After |
2x7 |
not given |
1x7 |
3x7 |
|
Charlie |
Adam |
Bryan |
Total of Charlie and Bryan |
Before |
18 u |
not given |
3 u |
21 u |
Change 1 |
- 20 |
+ 20 |
|
|
Change 2 |
|
- 20 |
+ 20 |
|
After |
14 u |
not given |
7 u |
21 u |
(a)
Change X times into units.
The total number of stickers of Charlie and Bryan remains unchanged.
LCM of 7 and 3 is 21.
Change in the number of stickers that Bryan has
= 7 u - 3 u
= 4 u
(b)
Difference in the number that Charlie and Bryan has in the end
= 14 u - 7 u
= 7 u
(c)
4 u = 20
(d)
1 u = 20 ÷ 4 = 5
Answer(s): (a) 4; (b) 7; (c) 4; (d) 5