Fill in the blanks.
Albert spends
19 of his money on 4 beads and 3 erasers.
Each eraser costs thrice as much as each bead.
Let the price of 1 bead be 1 u.
- Cost of 1 eraser = _____ u
- Amount that Albert has spent = _____ u
- Amount that Albert has left = _____ u
- Amount that Albert has at first = _____ u
(a)
Change X times into units.
Cost of 1 bead = 1 u
Cost of 1 eraser = 3 x 1 u = 3 u
(b)
Amount that Albert has spent
= 4 x 1 u + 3 x 3 u
= 4 u + 9 u
= 13 u
(c)
Fraction of the money he has left
= 1 -
19 =
89 19 of his money = 13 u
89 of his money = 8 x 13 u = 104 u
Amount that Albert has left = 104 u
(d)
Amount that Albert has at first
= 13 u + 104 u
= 117 u
Answer(s): (a) 3; (b) 13; (c) 104; (d) 117