Fill in the blanks.
Albert spends
110 of his money on 2 marbles and 5 beads.
Each bead costs four times as much as each marble.
Let the price of 1 marble be 1 u.
- Cost of 1 bead = _____ u
- Amount that Albert has spent = _____ u
- Amount that Albert has left = _____ u
- Amount that Albert has at first = _____ u
(a)
Change X times into units.
Cost of 1 marble = 1 u
Cost of 1 bead = 4 x 1 u = 4 u
(b)
Amount that Albert has spent
= 2 x 1 u + 5 x 4 u
= 2 u + 20 u
= 22 u
(c)
Fraction of the money he has left
= 1 -
110 =
910 110 of his money = 22 u
910 of his money = 9 x 22 u = 198 u
Amount that Albert has left = 198 u
(d)
Amount that Albert has at first
= 22 u + 198 u
= 220 u
Answer(s): (a) 4; (b) 22; (c) 198; (d) 220