Julie, Jaslyn and Fiona have equal number of beads. Julie packs all her beads equally into 8 packets. Jaslyn packs all her beads equally into 5 packets. Fiona packs all her beads equally into 10 packets. 5 packets of Julie's beads, 4 packets of Jaslyn's beads and 3 packets of Fiona's beads add up to 207 beads. How many beads do they have altogether?
| |
Julie |
Jaslyn |
Fiona |
| Number of packets |
8 |
5 |
10 |
| Number of beads |
40 u |
40 u |
40 u |
| Number of beads in each packet |
5 u |
8 u |
4 u |
All the beads can be put into the packets without remainder.
All the children have equal numbers of beads.
Make the number of beads that each child has the same. LCM of 8, 5 and 10 = 40
Number of beads that each child has = 40 u
Number of beads in 1 packet of Julie's beads = 40 u ÷ 8 = 5 u
Number of beads in 1 packet of Jaslyn's beads = 40 u ÷ 5 = 8 u
Number of beads in 1 packet of Fiona's beads = 40 u ÷ 10 = 4 u
Number of beads in 5 packets of Julie's beads, 4 packets of Jaslyn's beads and 3 packets of Fiona's beads
= (5 x 5 u) + (4 x 8 u) + (3 x 4 u)
= 25 u + 32 u + 12 u
= 69 u
69 u = 207
1 u = 207 ÷ 69 = 3
Total number of beads that they have
= 3 x 40 u
= 120 u
= 120 x 3
= 360
Answer(s): 360
