Victoria, Jade and Rachel have equal number of marbles. Victoria packs all her marbles equally into 8 packets. Jade packs all her marbles equally into 6 packets. Rachel packs all her marbles equally into 4 packets. 6 packets of Victoria's marbles, 5 packets of Jade's marbles and 2 packets of Rachel's marbles add up to 300 marbles. How many marbles do they have altogether?
|
Victoria |
Jade |
Rachel |
Number of packets |
8 |
6 |
4 |
Number of marbles |
24 u |
24 u |
24 u |
Number of marbles in each packet |
3 u |
4 u |
6 u |
All the marbles can be put into the packets without remainder.
All the children have equal numbers of marbles.
Make the number of marbles that each child has the same. LCM of 8, 6 and 4 = 24
Number of marbles that each child has = 24 u
Number of marbles in 1 packet of Victoria's marbles = 24 u ÷ 8 = 3 u
Number of marbles in 1 packet of Jade's marbles = 24 u ÷ 6 = 4 u
Number of marbles in 1 packet of Rachel's marbles = 24 u ÷ 4 = 6 u
Number of marbles in 6 packets of Victoria's marbles, 5 packets of Jade's marbles and 2 packets of Rachel's marbles
= (6 x 3 u) + (5 x 4 u) + (2 x 6 u)
= 18 u + 20 u + 12 u
= 50 u
50 u = 300
1 u = 300 ÷ 50 = 6
Total number of marbles that they have
= 3 x 24 u
= 72 u
= 72 x 6
= 432
Answer(s): 432