Ivory, Jen and Cindy have equal number of coins. Ivory packs all her coins equally into 4 packets. Jen packs all her coins equally into 8 packets. Cindy packs all her coins equally into 10 packets. 2 packets of Ivory's coins, 5 packets of Jen's coins and 3 packets of Cindy's coins add up to 228 coins. How many coins do they have altogether?

	Ivory	Jen	Cindy
Number of packets	4	8	10
Number of coins	40 u	40 u	40 u
Number of coins in each packet	10 u	5 u	4 u

All the coins can be put into the packets without remainder.

All the children have equal numbers of coins. 
Make the number of coins that each child has the same. LCM of 4, 8 and 10 = 40

Number of coins that each child has = 40 u

Number of coins in 1 packet of Ivory's coins = 40 u ÷ 4 = 10 u
Number of coins in 1 packet of Jen's coins = 40 u ÷ 8 = 5 u
Number of coins in 1 packet of Cindy's coins = 40 u ÷ 10 = 4 u

Number of coins in 2 packets of Ivory's coins, 5 packets of Jen's coins and 3 packets of Cindy's coins
= (2 x 10 u) + (5 x 5 u) + (3 x 4 u)
= 20 u + 25 u + 12 u
= 57 u

57 u = 228

1 u = 228 ÷ 57 = 4

Total number of coins that they have
= 3 x 40 u
= 120 u
= 120 x 4
= 480

Answer(s): 480