Roshel, Shiyun and Kimberly have equal number of stickers. Roshel packs all her stickers equally into 10 packets. Shiyun packs all her stickers equally into 8 packets. Kimberly packs all her stickers equally into 5 packets. 2 packets of Roshel's stickers, 5 packets of Shiyun's stickers and 4 packets of Kimberly's stickers add up to 260 stickers. How many stickers do they have altogether?

	Roshel	Shiyun	Kimberly
Number of packets	10	8	5
Number of stickers	40 u	40 u	40 u
Number of stickers in each packet	4 u	5 u	8 u

All the stickers can be put into the packets without remainder.

All the children have equal numbers of stickers. 
Make the number of stickers that each child has the same. LCM of 10, 8 and 5 = 40

Number of stickers that each child has = 40 u

Number of stickers in 1 packet of Roshel's stickers = 40 u ÷ 10 = 4 u
Number of stickers in 1 packet of Shiyun's stickers = 40 u ÷ 8 = 5 u
Number of stickers in 1 packet of Kimberly's stickers = 40 u ÷ 5 = 8 u

Number of stickers in 2 packets of Roshel's stickers, 5 packets of Shiyun's stickers and 4 packets of Kimberly's stickers
= (2 x 4 u) + (5 x 5 u) + (4 x 8 u)
= 8 u + 25 u + 32 u
= 65 u

65 u = 260

1 u = 260 ÷ 65 = 4

Total number of stickers that they have
= 3 x 40 u
= 120 u
= 120 x 4
= 480

Answer(s): 480