Anna, Tina and Ivory have equal number of cards. Anna packs all her cards equally into 7 packets. Tina packs all her cards equally into 4 packets. Ivory packs all her cards equally into 8 packets. 2 packets of Anna's cards, 3 packets of Tina's cards and 7 packets of Ivory's cards add up to 963 cards. How many cards do they have altogether?

	Anna	Tina	Ivory
Number of packets	7	4	8
Number of cards	56 u	56 u	56 u
Number of cards in each packet	8 u	14 u	7 u

All the cards can be put into the packets without remainder.

All the children have equal numbers of cards. 
Make the number of cards that each child has the same. LCM of 7, 4 and 8 = 56

Number of cards that each child has = 56 u

Number of cards in 1 packet of Anna's cards = 56 u ÷ 7 = 8 u
Number of cards in 1 packet of Tina's cards = 56 u ÷ 4 = 14 u
Number of cards in 1 packet of Ivory's cards = 56 u ÷ 8 = 7 u

Number of cards in 2 packets of Anna's cards, 3 packets of Tina's cards and 7 packets of Ivory's cards
= (2 x 8 u) + (3 x 14 u) + (7 x 7 u)
= 16 u + 42 u + 49 u
= 107 u

107 u = 963

1 u = 963 ÷ 107 = 9

Total number of cards that they have
= 3 x 56 u
= 168 u
= 168 x 9
= 1512

Answer(s): 1512