Kimberly, Gillian and Emily have equal number of stickers. Kimberly packs all her stickers equally into 6 packets. Gillian packs all her stickers equally into 8 packets. Emily packs all her stickers equally into 3 packets. 4 packets of Kimberly's stickers, 7 packets of Gillian's stickers and 2 packets of Emily's stickers add up to 477 stickers. How many stickers do they have altogether?
| |
Kimberly |
Gillian |
Emily |
| Number of packets |
6 |
8 |
3 |
| Number of stickers |
24 u |
24 u |
24 u |
| Number of stickers in each packet |
4 u |
3 u |
8 u |
All the stickers can be put into the packets without remainder.
All the children have equal numbers of stickers.
Make the number of stickers that each child has the same. LCM of 6, 8 and 3 = 24
Number of stickers that each child has = 24 u
Number of stickers in 1 packet of Kimberly's stickers = 24 u ÷ 6 = 4 u
Number of stickers in 1 packet of Gillian's stickers = 24 u ÷ 8 = 3 u
Number of stickers in 1 packet of Emily's stickers = 24 u ÷ 3 = 8 u
Number of stickers in 4 packets of Kimberly's stickers, 7 packets of Gillian's stickers and 2 packets of Emily's stickers
= (4 x 4 u) + (7 x 3 u) + (2 x 8 u)
= 16 u + 21 u + 16 u
= 53 u
53 u = 477
1 u = 477 ÷ 53 = 9
Total number of stickers that they have
= 3 x 24 u
= 72 u
= 72 x 9
= 648
Answer(s): 648
