Small papayas |
Medium papayas |
Large papayas |
$3 |
$7 |
$8 |
Caden had some papayas in 3 sizes. The number of medium papayas was four times the number of large papayas. The number of large papayas were five times the number of small papayas. He sold all the small and medium papayas. He received $144 from selling
25 of the large papayas.
- How many large papayas did he have at first?
- How much less did he collect from selling the small papayas than the medium papayas?
Small papayas |
Medium papayas |
Large papayas |
|
4x5 |
1x5 |
1x1 |
|
5x1 |
1 u |
20 u |
5 u |
(a)
The number of large papayas is the repeated identity. Make the number of large papayas the same. LCM of 1 and 5 is 5.
|
Small papayas |
Medium papayas |
Large papayas |
Before |
1 u |
20 u |
5 u |
Change |
- 1 u |
- 20 u |
- 2 u |
After |
0 |
0 |
3 u |
Number of large papayas that Caden sold
=
25 x 5 u
= 2 u
|
Small papayas |
Medium papayas |
Large papayas |
Number |
1 u |
20 u |
2 u |
Value |
$3 |
$7 |
$8 |
Total value |
3 u |
140 u |
16 u |
Amount that Caden received from selling of
25 of the large papayas = 16 u
16 u = 144
1 u = 144 ÷ 16 = 9
Number of large papayas at first
= 5 u
= 5 x 9
= 45
(b)
Amount that Caden collected less from selling the small papayas than the medium papayas
= 140 u - 3 u
= 137 u
= 137 x 9
= $1233
Answer(s): (a) 45; (b) $1233