Small papayas |
Medium papayas |
Large papayas |
$5 |
$6 |
$9 |
Elijah had some papayas in 3 sizes. The number of medium papayas was five times the number of large papayas. The number of large papayas were thrice the number of small papayas. He sold all the small and medium papayas. He received $378 from selling
23 of the large papayas.
- How many large papayas did he have at first?
- How much less did he collect from selling the small papayas than the medium papayas?
Small papayas |
Medium papayas |
Large papayas |
|
5x3 |
1x3 |
1x1 |
|
3x1 |
1 u |
15 u |
3 u |
(a)
The number of large papayas is the repeated identity. Make the number of large papayas the same. LCM of 1 and 3 is 3.
|
Small papayas |
Medium papayas |
Large papayas |
Before |
1 u |
15 u |
3 u |
Change |
- 1 u |
- 15 u |
- 2 u |
After |
0 |
0 |
1 u |
Number of large papayas that Elijah sold
=
23 x 3 u
= 2 u
|
Small papayas |
Medium papayas |
Large papayas |
Number |
1 u |
15 u |
2 u |
Value |
$5 |
$6 |
$9 |
Total value |
5 u |
90 u |
18 u |
Amount that Elijah received from selling of
23 of the large papayas = 18 u
18 u = 378
1 u = 378 ÷ 18 = 21
Number of large papayas at first
= 3 u
= 3 x 21
= 63
(b)
Amount that Elijah collected less from selling the small papayas than the medium papayas
= 90 u - 5 u
= 85 u
= 85 x 21
= $1785
Answer(s): (a) 63; (b) $1785