Howard had a total of 274 kiwis and pomegranates. He sold
25 of the pomegranates and bought another 12 kiwis. In the end, the number of kiwis he had was
12 the number of pomegranates. How many more pomegranates than kiwis did he have at first?
| |
Kiwis |
Pomegranates |
Total |
Before
|
3 u - 12
|
5x2 =
10 u |
274 |
Change |
+ 12 |
- 2x2 =
4 u |
|
| After |
|
3x2 =
6 u |
|
Comparing between
kiwis and pomegranates |
1x3 =
3 u |
2x3 =
6 u |
|
The number of pomegranates in the end is repeated. Make the number of pomegranates in the end the same. LCM of 3 and 2 is 6.
Total number of kiwis and pomegranates at first
= 3 u - 12 + 10 u
= 13 u - 12
13 u - 12 = 274
13 u = 274 + 12
13 u = 286
1 u = 286 ÷ 13 = 22
Number of more pomegranates than kiwis at first
= 10 u - (3 u - 12)
= 10 u - 3 u + 12
= 7 u + 12
= 7 x 22 + 12
= 154 + 12
= 166
Answer(s): 166
