Lee had a total of 684 pears and persimmons. He sold
14 of the persimmons and bought another 16 pears. In the end, the number of pears he had was
34 the number of persimmons. How many more persimmons than pears did he have at first?
| |
Pears |
Persimmons |
Total |
Before
|
9 u - 16
|
4x4 =
16 u |
684 |
Change |
+ 16 |
- 1x4 =
4 u |
|
| After |
|
3x4 =
12 u |
|
Comparing between
pears and persimmons |
3x3 =
9 u |
4x3 =
12 u |
|
The number of persimmons in the end is repeated. Make the number of persimmons in the end the same. LCM of 3 and 4 is 12.
Total number of pears and persimmons at first
= 9 u - 16 + 16 u
= 25 u - 16
25 u - 16 = 684
25 u = 684 + 16
25 u = 700
1 u = 700 ÷ 25 = 28
Number of more persimmons than pears at first
= 16 u - (9 u - 16)
= 16 u - 9 u + 16
= 7 u + 16
= 7 x 28 + 16
= 196 + 16
= 212
Answer(s): 212
