Harry had a total of 587 oranges and chikoos. He sold
13 of the chikoos and bought another 34 oranges. In the end, the number of oranges he had was
45 the number of chikoos. How many more chikoos than oranges did he have at first?
| |
Oranges |
Chikoos |
Total |
Before
|
8 u - 34
|
3x5 =
15 u |
587 |
Change |
+ 34 |
- 1x5 =
5 u |
|
| After |
|
2x5 =
10 u |
|
Comparing between
oranges and chikoos |
4x2 =
8 u |
5x2 =
10 u |
|
The number of chikoos in the end is repeated. Make the number of chikoos in the end the same. LCM of 2 and 5 is 10.
Total number of oranges and chikoos at first
= 8 u - 34 + 15 u
= 23 u - 34
23 u - 34 = 587
23 u = 587 + 34
23 u = 621
1 u = 621 ÷ 23 = 27
Number of more chikoos than oranges at first
= 15 u - (8 u - 34)
= 15 u - 8 u + 34
= 7 u + 34
= 7 x 27 + 34
= 189 + 34
= 223
Answer(s): 223
