Daniel had a total of 485 kiwis and pears. He sold
14 of the pears and bought another 37 kiwis. In the end, the number of kiwis he had was
35 the number of pears. How many more pears than kiwis did he have at first?
| |
Kiwis |
Pears |
Total |
Before
|
9 u - 37
|
4x5 =
20 u |
485 |
Change |
+ 37 |
- 1x5 =
5 u |
|
| After |
|
3x5 =
15 u |
|
Comparing between
kiwis and pears |
3x3 =
9 u |
5x3 =
15 u |
|
The number of pears in the end is repeated. Make the number of pears in the end the same. LCM of 3 and 5 is 15.
Total number of kiwis and pears at first
= 9 u - 37 + 20 u
= 29 u - 37
29 u - 37 = 485
29 u = 485 + 37
29 u = 522
1 u = 522 ÷ 29 = 18
Number of more pears than kiwis at first
= 20 u - (9 u - 37)
= 20 u - 9 u + 37
= 11 u + 37
= 11 x 18 + 37
= 198 + 37
= 235
Answer(s): 235
